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6 February, 08:19

Diatomic O2 can react with the element magnesium to form magnesium oxide (MgO). The balanced chemical equation is: O2 + 2 Mg → 2 MgO If 97.2 g grams of magnesium totally reacted with more than enough O2, how many moles of MgO would be expected to form?

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  1. 6 February, 10:50
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    We expected 4 moles of MgO to be formed. (This is 161.2 grams)

    Explanation:

    Step 1: The balanced equation

    O2 + 2 Mg → 2 MgO

    Step 2: Data given

    mass of Mg = 97.2 grams

    O2 = in excess

    Molar mass of Mg = 24.3 g/mol

    Molar mass of O2 = 32 g/mol

    Molar mass of MgO = 40.3 g/mol

    Step 3: Calculate moles of Mg

    moles Mg = 97.2 / 24.3 g/mol

    moles Mg = 4 moles

    Mg is the limiting reactant. It will completely react (4 moles). O2 is in excess. There will react 2 moles of 02.

    Step 4: Calculate moles of MgO

    For 2 moles Mg consumed, we need 1 mole O2 to produce 2 moles of MgO

    For 4 moles of Mg consumed, we have 4 moles of MgO produced.

    We expected 4 moles of MgO to be formed. (This is 161.2 grams)
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