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3 December, 19:16

How many moles of oxygen are needed to react with 6.78 grams of ammonia?

4NH3 + 5O2-> 4NO + 6 H2O

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  1. 3 December, 19:43
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    Answer: 0.499mol

    Explanation:

    4NH3 + 5O2 - > 4NO + 6H2O

    Molar Mass of NH3 = 14 + 3 = 17g/mol

    Mass conc. Of NH3 = 6.78g

    n = Mass conc. / molar Mass

    n = 6.78 / 17 = 0.399mol

    From the equation,

    4moles of NH3 required 5moles of O2.

    Therefore, 0.399mol of NH3 will require Xmole of O2. i. e

    Xmol of O2 = (0.399 x 5) / 4 = 0.499mol
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