Sodium chloride is produced from its elements

through a synthesis reaction. What mass of each

reactant would be required to produce 25.0 mol

of sodium chloride?

Mass of Sodium = 574.75 g

Mass of Chlorine = 886.25 g

Explanation:

The balance chemical equation for the synthesis of NaCl is,

2 Na + Cl₂ → 2 NaCl

Step 1: Find out moles of each reactant required,

According to balance chemical equation,

2 moles of NaCl is produced by = 2 moles of Na

So,

25 moles of NaCl will be produced by = X moles of Na

Solving for X,

X = 25 mol * 2 mol / 2 mol

X = 25 moles of Na

Similarly for Cl₂,

According to balance chemical equation,

2 moles of NaCl is produced by = 1 mole of Cl₂

So,

25 moles of NaCl will be produced by = X moles of Cl₂

Solving for X,

X = 25 mol * 1 mol / 2 mol

X = 12.5 moles of Cl₂

Step 2: Convert each moles to mass as;

Mass = Moles * Atomic Mass

For Na,

Mass = 25 mol * 22.99 g/mol

Mass = 574.75 g

For Cl₂,

Mass = 12.5 mol * 70.90 g/mol

Mass = 886.25 g