12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper (II) chloride are

obtained. Calculate the theoretical yield and the percent yield.

Percent yield = 94.5%

Theoretical yield = 26.89 g

Explanation:

Given dа ta:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂ → CuCl₂

Number of moles of Copper:

Number of moles = mass / molar mass

Number of moles = 12.5 g / 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

Cu : CuCl₂

1 : 1

0.2 : 0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles * molar mass

Mass = 0.2 mol * 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield * 100

Percent yield = 25.4 g/26.89 g * 100

Percent yield = 94.5%