Calculate the [ H + ] and pH of a 0.0040 M butanoic acid solution. The K a of butanoic acid is 1.52 * 10 - 5. Use the method of successive approximations in your calculations.

Question

Chemistry

Friday

29 October, 23:59

Calculate the [ H + ] and pH of a 0.0040 M butanoic acid solution. The K a of butanoic acid is 1.52 * 10 - 5. Use the method of successive approximations in your calculations.

+3

Answers (1)

Know the Answer?

Mays · Answer 1

Ka = [H+][But-]/H[Hbut]

Let k moles of H + be formed

1.52*10^-5=k^2/0.004-k

K^2=0.004*1.52*10^-5-1.52*10^-5k

K^2 - 1.52*10^-5k-6.08*10^-8=0

Solving this quadratic equation.

K=7.6*10^-6

PH=-log (7.6*10^-6) = 5.2