Identify the oxidizing agent in the reaction: Sn (s) + 2H + (aq) → Sn2 + (aq) + H2 (g) Sn2 + H2 H + Sn

H⁺ (aq)

Explanation:

Let's consider the following redox reaction.

Sn (s) + 2 H⁺ (aq) → Sn²⁺ (aq) + H₂ (g)

We can identify both half-reactions.

Oxidation: Sn (s) → Sn²⁺ (aq) + 2 e⁻

Reduction: 2 H⁺ (aq) + 2 e⁻ → H₂ (g)

Sn (s) undergoes oxidation so it is the reducing agent, while H⁺ (aq) undergoes reduction so it is the oxidizing agent.