Question 6

A 9.0-kg crate rests on a frictionless surface. It then experiences a net horizontal force of 45. newtons. What is the resulting acceleration of the crate?

A

0.0 m/s2

B

0.20 m/s2

C

5.0 m/s2

D

36 m/s2

C 5.0 m/s²

Explanation:

Given data

Mass (m) : 9.0 kg

Force (F) : 45 N

A 9.0-kg crate rests on a frictionless surface, thus, the only horizontal force to consider is that of 45 N. We can find the acceleration of the 9.0-kg crate due to the 45 N force using Newton's second law of motion.

F = m * a

a = F/m = 45 N/9.0 kg = 5.0 m/s²

the answers 5, also did u finish ur ia yet,

if so you know what to do.