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14 June, 03:26

How many moles of BaCl2 are found in 8.62grams of BaCl2?

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Answers (2)
  1. 14 June, 06:33
    0
    Answer: 0.04137 moles

    Explanation:

    Ba = 137.327amu

    Cl = 35.5

    BaCl2 = 137.327 + (35.5*2)

    BaCl2 = 137.327 + 71

    BaCl2 = 208.327amu

    1 mole of BaCl2 contains 208.327 g

    x mole is present in 8.62g of BaCl2

    x = 8.62 * 1 / 208.327

    x = 0.04137g
  2. 14 June, 06:34
    0
    Answer: 0.0416 moles BaCl2 or 4.16x10-2 moles BaCl2

    Explanation: solution just multiply the given value 8.62g x 1mol BaCl2/207g which is the molar mass of barium chloride.
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