a mixture of 2 moles of Ne gas and 3 moles of Ar gas are kept in a cylinder at 25.0 degress celcious. what is the indivual pressure of each and the total pressure?

Hey there!

Assuming the volume of the cylinder is 1 L.

Given, T=25 = 298K

As per the Dalton's law, total P = PNe + PAr ... where PNe = partial pressure of Ne and PAr = partial pressure of Ar.

PV = nRT

total P = (total moles) * (0.082057 L atm mol-1K-1 * 298) / 1 = 5*0.082057*298 = 122.27 atm.

PNe = mole fraction of Ne * total P = (2/5) * 122.27 = 48.908 atm

PAr = mole fraction of Ar * total P = (3/5) * 122.27 = 73.362 atm

Total pressure is 122.27 atm

Ne pratial pressure = 48.908 atm

Ar prtial pressure = 73.362 atm