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16 June, 20:26

Calculate the vapor pressure of water above a solution prepared by dissolving 29.0 g of glycerin (C3H8O3) in 120 g of water at 343 K.

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  1. 16 June, 21:44
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    The vapor pressure is 223.28 mmHg

    Explanation:

    Step 1: Data given

    Mass of glycerin = 29.0 grams

    Mass of water = 120.0 grams

    Molar mas glycerin = 92.09 g/mol

    Molar mass water = 18.02 g/mol

    Temperature = 343 K

    The vapor pressure for 343 K is 233.7 mmHg

    Step 2: Calculate moles glycerin

    Moles glycerin = mass glycerin / molar mass glycerin

    Moles glycerin = 29.00 grams / 92.09 g/mol

    Moles glycerin = 0.315 moles

    Step 3: Calculate moles water

    Moles water = 120.0 grams / 18.02 g/mol

    Moles water = 6.66 moles

    Step 4: Calculate total moles

    Total moles = 0.315 moles + 6.66 moles = 6.975 moles

    Step 5: Calculate mol fraction H2O:

    Mol fraction H2O = 6.66 moles / 6.975 moles = 0.955

    Step 6: Calculate vapor pressure

    Vapor pressure = mol fraction H2O * Vapor pressure H2O (at 343 K)

    Vapor pressure = 0.955 * 233.8 mmHg

    Vapor pressure = 223.28 mmHg

    The vapor pressure is 223.28 mmHg
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