For the following reaction, calculate how many moles of NO2 forms when 0.356 moles of the reactant completely reacts.

2 N2O5g→4 NO2g+O2g

0.712 mol of NO₂ are formed.

Explanation:

For the reaction, given in the question,

2 N₂O₅ (g) → 4 NO₂ (g) + O₂ (g)

From the above balanced reaction,

2 mol of N₂O₅ reacts to give 4 mol of NO₂

Applying unitary method,

1 mol of N₂O₅ reacts to give 4 / 2 mol of NO₂

From the question, 0.356 mol of N₂O₅ are reacted,

now, using the above equation, to calculate the moles of the NO₂, as follow -

Since,

1 mol of N₂O₅ reacts to give 4 / 2 mol of NO₂

0.356 mol of N₂O₅ reacts to give 4 / 2 * 0.356 mol of NO₂

Calculating,

0.712 mol of NO₂ are formed.