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11 May, 15:24

What pressure will be needed to lwave the vloume of 77.4L ay helium at 98. OK pa to a vloume of 60.0L

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  1. 11 May, 18:00
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    P₂ = 126.42 kpa

    Explanation:

    Given dа ta:

    Initial volume = 77.4 L

    Initial pressure = 98.0 Kpa

    Final volume = 60.0 L

    Final pressure = ?

    Solution:

    Formula:

    P₁V₁ = P₂V₂

    P₁ = Initial pressure

    V₁ = Initial volume

    P₂ = Final pressure

    V₂ = Final volume

    Now we will put the values in formula.

    P₁V₁ = P₂V₂

    98.0 kpa * 77.4 L = P₂ * 60.0 L

    7585.2 Kpa. L = P₂ * 60.0 L

    P₂ = 7585.2 Kpa. L / 60.0 L

    P₂ = 126.42 kpa
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