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4 January, 10:47

A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.

What volume of the

12.0 M HCl should he/she start with?

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Answers (1)
  1. 4 January, 13:20
    0
    4.74 mL

    Explanation:

    M1V1 = M2V2

    12.0M*V1 = 0.875M*65.0 mL

    V1 = 0.875M*65.0 mL/12.0M = 4.74 mL
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