Approximately how many moles of Al3 + are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3 + available and that Al3 + is reduced to Al metal only.)

A. 0.033 molB. 0.050 molC. 0.067 molD. 0.10 mol

Question

Chemistry

Genesis Holland

15 December, 13:38

Approximately how many moles of Al3 + are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3 + available and that Al3 + is reduced to Al metal only.)

A. 0.033 molB. 0.050 molC. 0.067 molD. 0.10 mol

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Answers (1)

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Cynthia · Answer 1

0.033 mol

Explanation:

1 faraday is require to 1 mol of electron

0.1 faraday is required for 0.1 mol of electron

3 mol of electron is required for 1 mole Al3 + to Al

0.1 mole of electron will therefore need (0.1 mol * 1 mol) / 3 mol = 0.033 mol

Approximately how many moles of Al3 + are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3 + available and that Al3 + is reduced to Al metal only.)A. 0.033 molB. 0.050 molC. 0.067 molD. 0.10 mol

Approximately how many moles of Al3 + are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3 + available and that Al3 + is reduced to Al metal only.)

A. 0.033 molB. 0.050 molC. 0.067 molD. 0.10 mol