What is the pH of a solution made by diluting 1.00 mL of 0.10 M HCl with enough distilled water to make 1.00 L of solution?

The answer to your question is pH = 4

Explanation:

Data

Volume 1 = V1 = 1 ml = 0.001 l

Concentration 1 = C1 = 0.1 M

Volume 2 = V2 = 1 l

Concentration 2 = C2 = ?

Process

1. - Find the new concentration of the solution

C₁V₂ = C₂V₂

Solve for C₂

C₂ = C₁V₁ / V₂

Substitution

C₂ = (0.1 x 0.001) / 1

Result

C₂ = 0.0001 M

2. - Find the pH of the solution

Formula

pH = - log[H⁺]

Substitution

pH = - log[0.0001]

Simplification

pH = 4