A bomb calorimeter has a heat capacity of 2.18 kJ/K. When a 0.176g sample of gas with a molar mass of 28.0 g/mol was burned in this calorimeter, the temperature increases by 2.12 K. Calculate the heat of combustion for 1 mol of this gas. - 1.29 x 10^2 kJ - 4.62 kJ - 2.63 x 10 kJ - 0.0291 kJ - 7.35 x 10^2 kJ

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Chemistry

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22 January, 04:37

A bomb calorimeter has a heat capacity of 2.18 kJ/K. When a 0.176g sample of gas with a molar mass of 28.0 g/mol was burned in this calorimeter, the temperature increases by 2.12 K. Calculate the heat of combustion for 1 mol of this gas. - 1.29 x 10^2 kJ - 4.62 kJ - 2.63 x 10 kJ - 0.0291 kJ - 7.35 x 10^2 kJ

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Answers (1)

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Stanley Holloway · Answer 1

Heat of combustion = -7.35 * 10² kJ

Explanation:

Step 1: Data given

Mass = 0.176 grams

Molar mass = 28.0 g/mol

Temperature increase 2.12 K

A bomb calorimeter has a heat capacity of 2.18 kJ/K

Step 2: Calculate heat of combustion

Energy released = mass * heat capacity * change in temperature

Q = c*∆T

Q = 2.18 kJ/K*2.12 K = 4.62 kJ released

Heat of combustion = (energy released) / (mole of substance)

Moles of gas = (0.176 g) / (28.0 g/mol) = 0.00629 moles

Heat of combustion = (energy released) / (mole of substance)

Heat of combustion = (4.62 kJ) / (0.00629 moles) = 7.35 * 10² kJ

Heat of combustion = -7.35 * 10² kJ (negative because heat is lost)