An experiment requires 62.7 g of ethyl alcohol (density = 0.790 g/mL). What volume, in liters, will be required?

Answer: 0.0794 L or 7.94x10-2L

Explanation:

Density is expressed by D = m/V mass over volume.

62.7 g / 0.790 g/mL = 79.4 mL

Convert this into L by dividing it to 1000. So the result is 0.0794 L

0.0794 L

Explanation:

An experiment requires 62.7 g of ethyl alcohol. The density of ethyl alcohol is 0.790 g/mL. The volume, in milliliters, corresponding to 62.7 g of ethyl alcohol is:

62.7 g * (1 mL/0.790 g) = 79.4 mL

1 liter is equal to 1000 milliliters. The volume, in liters, corresponding to 79.4 mL is:

79.4 mL * (1 L / 1000 mL) = 0.0794 L