How many total moles of ions are released when the following sample dissolves completely in water?

7.1 mol of NH4Cl

8.55 * 10²⁴ Ions

Explanation:

Ammonium Chloride is an ionic compound which contains a monatomic anion (Cl⁻; Chloride) and a polyatomic cation (NH₄⁺; Ammonium).

Hence, when added in water Ammonium Chloride ionizes as;

NH₄Cl → NH₄⁺ + Cl⁻

Hence, we can say that it produces two ions when dissolved in water.

Also,

We know that 1 mole of any substance contains exactly 6.022 * 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of ions contained by 7.1 moles of NH₄Cl, we will use following relation to first calculate the number of molecules as;

Moles = Number of Molecules : 6.022 * 10²³ Molecules. mol⁻¹

Solving for Number of Molecules,

Number of Molecules = Moles * 6.022 * 10²³ Molecules. mol⁻¹

Putting values,

Number of Molecules = 7.1 mol * 6.022 * 10²³

Number of Molecules = 4.27 * 10²⁴ Molecules

So,

As,

1 Molecule of NH₄Cl contained = 2 Ions

So,

4.27 * 10²⁴ Molecules of NH₄Cl will contain = X ions

Solving for X,

X = 2 Ions * 4.27 * 10²⁴ Molecules / 1 Molecule

X = 8.55 * 10²⁴ Ions