How many moles of calcium carbonate-CaCO3 = 4.15 g

Question

Chemistry

Ethan Turner

9 May, 00:34

How many moles of calcium carbonate-CaCO3 = 4.15 g

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Answers (1)

Know the Answer?

Greta Harding · Answer 1

Number of moles = 0.042 mol

Explanation:

Given dа ta:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass / molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12 + 3*16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol