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3 October, 18:55

What volume of a 4.5 m solution of phosphate is necessary to create a 80.0 ml stock of 2.0 m phosphate solution?

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  1. 3 October, 21:26
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    Answer: V1 = 45.6 ml

    Explanation:

    This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.

    The dilution equation will be used. The equation is as follows:

    M1V1 = M2V2 where

    V1 = Initial volume of phosphate solution.

    M1 = Initial concentration of phosphate solution.

    V2 = Final volume of phosphate solution.

    M2 = Final concentration of phosphate solution.

    From the information given,

    M1 = 4.5

    V1 = ?

    M2 = 2.0

    V2 = 80

    4.5 * V1 = 2*80

    4.5V1 = 160

    V1 = 160/4.5

    = 35.6 ml
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