2NBr3 + 3NaOH - N2 + 3NaBr + 3HBrO

How many NaBr formula units are formed when 50 NBrz

molecules and 57 NaOH formula units react? (Formula units are

the equivalent of molecules for ionic compounds.)

50 formula units of NBr3 will yield 75 formula units of NaBr

57 formula units of NaOH will yield 57 formula units of NaBr

Explanation:

The equation of the reaction is;

2NBr3 + 3NaOH - N2 + 3NaBr + 3HBrO

Number of formula units of NaBr formed when 50NBr3 reacts was obtained from;

2 formula units of NBr3 yields 3 formula units of NaBr

50 formula units of NBr3 will yield 50 * 3/2 = 75 formula units of NaBr

Hence 50 formula units of NBr3 will yield 75 formula units of NaBr

Then;

Since 3 formula units of NaOH yields 3 formula units of NaBr

57 formula units of NaOH will yied 57*3/3 = 57 formula units of NaBr

Hence 57 formula units of NaOH will yield 57 formula units of NaBr