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1 May, 08:03

How many grams of Na2SO4 should be weighed out to prepare 0.5L of a 0.100M solution?

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  1. 1 May, 08:20
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    7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.

    Explanation:

    First of all the molecular weight of Na2SO4 is 142.08 gram. Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.

    According to the given question we have to prepare 0.100 M solution

    1000 ml of solution contain 142.08*0.1 = 14.208 gram Na2SO4

    1 ml of solution contain 14.208:1000 = 0.014 gram

    0.5L or 500ml of solution contain 0.014*500 = 7gram Na2SO4.

    So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
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