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8 October, 16:15

In an experiment, a student estimates the acceleration due to gravity is 9.31 m/s2. The actual value is 9.8 m/s2. What is the student's percent error

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Answers (2)
  1. 8 October, 17:13
    0
    The answer is 5% error rate

    Explanation:

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    Let's solve this!

    The data we have are:

    Actual Gravity = 9.8m / s2

    measured severity = 9.31m / s2

    The% error is measured with the following formula:

    % error = ((actual value-measured value) / actual value) * 100

    % error = (9.8-9.31) / 9.8) * 100

    % error = 5%

    The answer is 5% error rate
  2. 8 October, 18:42
    0
    The percent error of student is - 5 %.

    Explanation:

    Given dа ta:

    measured value = 9.31 m/s²

    actual value = 9.8 m/s²

    percent error = ?

    Formula:

    % error = (measured value - actual value / actual value) * 100

    % error = (9.31 m/s² - 9.8 m/s² / 9.8 m/s²) * 100

    % error = (-0.49 m/s² / 9.8 m/s²) * 100

    % error = - 0.05 * 100

    % error = - 5
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