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14 June, 15:14

10. What is the molarity of a MnO4 - solution if 23.5 mL of this solution is required to react completely with 30.0 mL of 0.134 M Fe2 solution according to the equation 5Fe2 (aq) MnO4 - (aq) 8H (aq) - --> 5Fe3 (aq) Mn2 (aq) 4H2O (l)

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  1. 14 June, 18:21
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    The molarity of a MnO4 - solution

    = 0.0342 M

    Explanation:

    Equation of reaction:

    5Fe2 (aq) MnO4 - (aq) 8H (aq) - --> 5Fe3 (aq) Mn2 (aq) 4H2O (l)

    This is an example of redox titration.

    Using titration formula:

    CAVA/CBVA = NA/NB

    where CA is the molarity of Fe2 + = (0.134 M)

    CB is the molarity of MnO4 - = (?)

    VA is the volume of Fe2 + = (30mL)

    VB is the volume of MnO4 - = (23.5mL)

    NA is the numeric coefficient of Fe2 + in the equation of reaction = (5)

    NB is the numeric coefficient of MnO4 - in the equation of reaction = (1)

    Substituting the values into the formula;

    0.134*30/CB*23.5 = 5/1

    Therefore CB = 0.134*30/23.5*5

    = 0.0342 M
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