Which of the following would have to lose three electrons in order to achieve a noble gas electron configuration?

Si Mg Al Cl P

a. Cl

b. P

c. Mg, Al, P

d. Al

e. Si, P

Question

Chemistry

Darren Graham

21 April, 08:02

Which of the following would have to lose three electrons in order to achieve a noble gas electron configuration?

Si Mg Al Cl P

a. Cl

b. P

c. Mg, Al, P

d. Al

e. Si, P

+4

Answers (1)

Know the Answer?

Elian Burke · Answer 1

i believe the answer is Aluminum (Al)

Explanation:

Each element has an equal amount of protons to electron so i you subtract one of either you will have to subtract from the other to make sure it is stable. aluminum has 13 protons and electrons. Subtracting 3 from it would gkve it the same qualities as Neon.

Which of the following would have to lose three electrons in order to achieve a noble gas electron configuration?Si Mg Al Cl Pa. Clb. Pc. Mg, Al, Pd. Ale. Si, P

Which of the following would have to lose three electrons in order to achieve a noble gas electron configuration?

Si Mg Al Cl P

a. Cl

b. P

c. Mg, Al, P

d. Al

e. Si, P