Ask Question
4 April, 22:58

A weather balloon is inflated to a volume of 25.4 L at a pressure of 743 mmHg and a temperature of 25.8 ∘C. The balloon rises in the atmosphere to an altitude where the pressure is 400. mmHg and the temperature is - 13.0 ∘C. Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude

+3
Answers (2)
  1. 4 April, 23:44
    0
    41.45 l.

    Explanation:

    Using gas equation,

    (P1V1) / T1 = (P2V2) / T2

    P1 = initial pressure

    = 743 mmhg

    = 99.73 kPa

    V1 = initial volume

    = 25.4 l

    T1 = initial absolute temperature

    = 25.8 + 273.15

    = 298.95 K

    P2 = final pressure

    = 400 mmhg

    = 53.33 kPa

    T2 = final absolute temperature

    = 273.15 + (-13)

    = 260.15 K

    V2 = (99.73 * 25.5 * 260.15) / (298.95 * 53.33)

    = 41.45 l.
  2. 5 April, 00:10
    0
    41.09L

    Explanation:

    i applied the combine formula of chrles and boyles law
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A weather balloon is inflated to a volume of 25.4 L at a pressure of 743 mmHg and a temperature of 25.8 ∘C. The balloon rises in the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers