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6 July, 01:01

How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat

of H, 0 is 4.1841/gC)

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  1. 6 July, 01:58
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    q = mc theta

    where,

    Q = heat gained

    m = mass of the substance = 670g

    c = heat capacity of water = 4.1 J/g°C

    theta = Change in temperature = (66-25.7)

    Now put all the given values in the above formula, we get the amount of heat needed.

    q = mctheta

    q=670*4.1 * (66-25.7)

    =670*4.1*40.3

    =110704.1
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