A Chemist prepares a solution of sodium nitrate (NaNO3) by measuring out 122. g of sodium nitrate into 250. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium nitrate solution. Round your answer to 3 significant digits.

[NaNO₃] = 5.72 M

Explanation:

Molarity is a sort of concentration.

It says the moles of solute, that are contained in 1L of solution.

The volume is in mL, so let's convert to L.

250 mL. 1 L / 1000 mL = 0.250 L

Let's convert now, the mass of NaNO₃, our solute into moles

122 g / 85 g/mol = 1.43 moles

Molarity = mol / L → 1.43 mol / 0.250L = 5.72 M