A scientist wants to make a solution of tribasic solution phosphate, na3po4, for a laboratory experiment. How many grams of na3po4 will be needed to produce 675 ml of a solution that has a concentration of na + ions of 1.50 m

55.75g

Explanation:

From

m/M = CV

Where

m = required mass of solute

M = molar mass of solute

C = concentration of solution

V = volume of solution=675ml

Molar mass of solute = 3 (23) + 31 + 4 (16) = 69+31+64=164gmol-1

Number of moles of sodium ions present = 1.5 * 675/1000 = 1.01 moles

Since 1 mole of Na3PO4 contains 3 moles of Na+

It implies that 1.01/3 moles of Na3PO4 are present in solution = 0.34moles

mass of Na3PO4 = number of moles * molar mass = 0.34 * 164 = 55.75g