What is the correct balanced equation for the following:

potassium iodide + lead (II) sulfide - -> lead (ii) iodide + potassium sulfide

(A) 2KI + PbS - > Pbl2, + K2S

(B) KI + PbS-> Pbl + KS

(C) KI + Pb25 - > Pb2l + KS

(D) 2KI + Pb25 - > Pb2l2 + K2s

Question

Destiney Reed

2 June, 04:56

+2

Answers (1)

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Tyrell · Answer 1

A)

K has a positive charge of 1

I has a negative charge of 1

S has a negative charge of 2

Pb has a positive charge of 2

2KI + PbS - > PbI2 + K2S

What is the correct balanced equation for the following:potassium iodide + lead (II) sulfide - -> lead (ii) iodide + potassium sulfide(A) 2KI + PbS - > Pbl2, + K2S(B) KI + PbS-> Pbl + KS(C) KI + Pb25 - > Pb2l + KS(D) 2KI + Pb25 - > Pb2l2 + K2s