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30 August, 08:58

How would you solve this?

"Calculate the amount of energy transferred if only 650.50 grams of sulfur trioxide (SO3) gas were produced. (Remember the ∆H = - 396.8 kJ is part of the balanced equation) "

balanced equation: 2 SO2 (g) + O2 (g) ⇌ 2 SO3 (g) ∆H = - 396.8 kJ

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  1. 30 August, 09:42
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    1.6*10^3 KJ

    Explanation:

    We must first calculate the number of moles corresponding to 650.50g of sulphur trioxide.

    Number of moles = mass of sulphur trioxide / molar mass of sulphur trioxide

    Molar mass of sulphur trioxide = 80.066 g/mol

    Given mass of sulphur trioxide = 650.50g

    Number of moles = 650.50g / 80.066 g/mol

    Number of moles = 8.124 moles of sulphur trioxide

    Now from the balanced reaction equation;

    Formation of 2 moles of sulphur trioxide evolves 396.8KJ of energy.

    Therefore formation of 8.124 moles of sulphur trioxide will evolve;

    8.124moles * 396.8 KJ / 2 moles = 1611.8KJ or 1.6*10^3 KJ
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