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15 May, 10:02

In a calorimetry experiment, it was determined that a 92.0 gram piece of copper metal released 1860 J of heat to the surrounding water in the calorimeter (qcopper = - 1860 J). If the final temperature of the copper metal-water mixture was 25.00°C, what was the initial temperature of the copper metal? The specific heat of copper is 0.377 J / (g°C). Group of answer choices Tinitial = 28.6°C Tinitial = - 28.6°C Tinitial = 78.6°C Tinitial = 92.6°C Tinitial = 53.6°C

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  1. 15 May, 11:24
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    Tinitial = 78.6°C

    Explanation:

    In a calorimetry experiment, the flow heat is measured for a system that has a state change. In this case, there isn't happening a physical change, so the heat is called sensitive heat, and it's calculated by:

    q = mxCpxΔT

    Where q is the heat, m is the mass, Cp is the specific heat and ΔT is the difference of final and initial temperature (Tfinal - Tinitial).

    Copper is losing heat, so q is negative, then:

    -1860 = 92x0.377x (25 - Ti)

    34.684 (25 - Ti) = - 1860

    25 - Ti = - 53.63

    -Ti = - 78.63

    Ti = 78.6ºC
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