4fe (s) + 3o2 (g) →2fe2o3 (s) how many grams of Fe2O3 are produced when 12.0 of iron rusts

Mass = 10.1 g

Explanation:

Given dа ta:

Mass of Fe₂O₃ produced = ?

Mass of iron rust = 12.0 g

Solution:

Chemical equation:

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of iron:

Number of moles = mass / molar mass

Number of moles = 12.0 g / 55.85 g/mol

Number of moles = 0.215 mol

Now we will compare the moles of iron and Fe₂O₃.

Fe : Fe₂O₃

4 : 2

0.215 : 2/4*0.125 = 0.063 mol

Mass of Fe₂O₃:

Mass = number of moles * molar mass

Mass = 0.063 mol * 159.7 g/mol

Mass = 10.1 g