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16 February, 02:31

One way to experimentally measure the heat capacity of a Styrofoam cup calorimeter would be to melt a known mass of ice in warm water and measure hte temperature change. Use the data below to determine the experimental heat capacity of the calorimeter. Use the literature heat of fusion for ice in your calculations. Assume the ice added is at 0.00 c. Mass of ice added: 17.69gMass of water in calorimeter: 98.67gT-Initial of water: 28.7T-Final of water after melting ice: 12.9C

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  1. 16 February, 03:44
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    4.88 Cals per degree celsius

    Explanation:

    We have taken heat of fusion of ice = 80 cals / g

    We have taken speciic heat of water = 1 cal/g per degree celsius

    In this experiment, let the heat capacity of calorimeter be X.

    Heat gained by ice

    heat gained in melting + heat gained in getting warmed

    = mass x latent heat + mass x specific heat x rise in temperature

    = 17.69 x 80 + 17.69 x 1 x (12.9 - 0)

    = 1643.4 Cals

    Heat lost by water

    = mass x specific heat x fall in temperature

    98.67 x 1 x (28.77 - 12.9)

    = 1565.89 Cals

    Heat lost by calorimeter

    heat capacity x fall in temperature

    X x (28.77 - 12.9)

    Heat gained = heat lost

    1643.4 = 1565.89 + 15.87X

    X = 4.88 Cals per degree celsius
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