What would be the temperature change 3.0 g of water absorbed 15 J of heat

1.2 °C

Step-by-step explanation:

The formula relating the heat (q) absorbed by an object, the mass (m), and the temperature change (ΔT) is

q = mCΔT Divide both sides by mC

ΔT = q / (mC)

dа ta:

q = 15 J

m = 3.0 g

C = 4.184 J·°C⁻¹g⁻¹

Calculation:

ΔT = 15 / (3.0 * 4.184)

ΔT = 15/12.6

ΔT = 1.2 °C