Ask Question
18 December, 23:42

A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume

becomes 15.0L

A) 0.64L

B) 1.2kPa

C) 0.64kPa

D) 1.2L

+2
Answers (2)
  1. 19 December, 00:49
    0
    The correct answer is C) 0.64kPa
  2. 19 December, 03:16
    0
    Answer: Option C) 0.64kPa

    Explanation:

    Given that,

    Original volume V1 = 11.2 L

    original pressure P1 = 0.860kPa

    New volume V2 = 15.0 L

    New pressure P2 = ?

    Since pressure and volume are involved while temperature is constant, apply Boyle's law

    P1V1 = P2V2

    0.860 kPa x 11.2 L = P2 x 15.0L

    9.632 kPaL = P2 x 15.0L

    P2 = 9.632 kPaL / 15.0L

    P2 = 0.64 kPa

    Thus, the pressure of the gas is 0.64kPa
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume becomes 15.0L A) 0.64L B) 1.2kPa C) 0.64kPa D) 1.2L ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers