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15 May, 21:41

how many grams of calcium oxide are producer from the decomposition of 125 grams of calcium carbonate

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  1. 16 May, 00:39
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    70.0 g. The decomposition of 125 g CaCO3 produces 700 g CaO.

    MM = 100.09 56.08

    CaCO3 → CaO + CO2

    Mass 125 g

    a) Moles of CaCO3 = 125 g CaCO3 x (1 mol CaCO3/100.09 g CaCO3)

    = 1.249 mol CaCO3

    b) Moles of CaO = 1.249 mol CaCO3 x (1 mol CaO/1 mol CaCO3)

    = 1.249 mol CaO

    c) Mass of CaO = 1.249 mol CaO x (56.08 g CaO/1 mol CaO) = 70.0 g
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