If you purchased 2.31 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?

8.547 x 10⁴disintegrations per second

Explanation:

To calculate the disintegrations per second as -

Given,

2.31 μCi of sulfur - 35.

Since,

1 Ci = 3.7 * 10 ¹⁰ Bq

1 μCi = 10 ⁻⁶ Ci

Hence,

conversation is done as follows -

2.31 (1 * 10⁻⁶) * (3.7 * 10¹⁰)

= 8.547 x 10⁴

Hence,

8.547 x 10⁴disintegrations per second, the sample undergo for it to be brand new.