For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca (NO3) 2 how many moles of silver iodide will be produced from 205g of calcium iodide

Moles of silver iodide produced = 1.4 mol

Explanation:

Given dа ta:

Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

Solution:

Chemical equation:

CaI₂ + 2AgNO₃ → 2AgI + Ca (NO₃) ₂

Number of moles calcium iodide:

Number of moles = mass / molar mass

Number of moles = 205 g / 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

CaI₂ : AgI

1 : 2

0.7 : 2*0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.