Find molarity of 29.1 g LiClO4 · 3 H2O in 235 mL of solution

To find molarity

We need no. of moles and solution in liter

Given data is in grams and ml

We have to convert it in required units

For no. of moles use formula

No. of mole=mass in gram / molar mass

Mass in gram = 29.1g

Molar mass = 160.4374g/mol calculated by adding the atomic wight of all atoms in LiClO4.3H2O

Atomic weight

Li = 6.941

Cl = 35.453

O = 15.9994

H = 1.00794

Now put it in mol equation

No. of mole = 29.1/160.4374

= 0.181mol of solute

Now convert solution in L from ml

235ml = 235/1000 = 0.235L

Now put these values in molarity formula

Molarity = 0.181/0.235

= 0.77M solution