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23 April, 11:05

For a reaction in a voltaic cell, both ΔH° and ΔS° are positive. Given the following equations for standard free energy, ΔG° = ΔH° - TΔS°; ΔG° = - nFE°. How does the standard cell potential change with increasing temperature? Derive the equation that shows how the standard cell potential change with temperature

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  1. 23 April, 14:30
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    The standard cell potential increases with increasing temperature.

    Explanation:

    Equatio 1: ΔG° = ΔH° - TΔS°

    Equation 2: ΔG° = - nFE°

    Isolating E° in equation 2:

    E° = - ΔG° / nF (Equation 3)

    Substituting equation 1 in equation 3:

    E° = ( - ΔH° + TΔS°) / nf

    We can rearrange the equation:

    E° = (ΔS°/nF) T + (ΔH°/nF)

    Now it is clear that the higher the temperature, the higher the standard cell potential.
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