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17 February, 22:53

A sample of gas contains 6.25 * 10-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals? Which variables are given? pressure volume temperature moles

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  1. 18 February, 01:45
    0
    55.9 kPa; Variables given = volume (V), moles (n), temperature (T)

    We must calculate p from V, n, and T, so we use the Ideal Gas Law:

    pV = nRT

    Solve for p: p = nRT/V

    R = 8.314 kPa. L. K^ (-1). mol^ (-1)

    T = (265 + 273.15) K = 538.15 K

    V = 500.0 mL = 0.5000 L

    ∴ p = [6.25 x 10^ (-3) mol x 8.314 kPa·L·K^ (-1) ·mol^ (-1) x 538.15 K] / (0.5000 L) = 55.9 kPa
  2. 18 February, 02:41
    0
    Which variables are given?

    Answer:

    volume

    temperature

    moles

    Which variables are unknown?

    Answer:

    pressure

    Select the correct algebraic form for the equation to be used for this calculation.

    Answer:

    p = nRT/V

    Solve the problem for the pressure of oxygen.

    Answer:

    55.9 kPa
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