When 1.98 g of NaOH (molar mass = 40 g/mole) are added to 75.0 mL of a 0.350 M HCl solution in a coffee-cup calorimeter, the temperature changes from 21.7°C to 25.8°C. If the resulting solution has a mass of 78.2 grams and a specific heat capacity of 3.97 J/g°C, what is the enthalpy change (ΔHrxn) for this reaction in kJ/mole.

Question

Nigel Sanford

13 February, 02:55

+1

Answers (1)

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Joslyn Rivera · Answer 1

(ΔHrxn) = 1.273kJ/mol

Explanation:

Applying

m=78.2, c = 3.97, ∆t = 25.8-21.7

(ΔHrxn) = mc∆t

=78.2 * 3.97 * 4.1 = 1.273kJ/mol