Ask Question
9 April, 11:20

The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased to 115 kPa?

+4
Answers (1)
  1. 9 April, 13:21
    0
    Solubility is 1.265g/L

    Explanation:

    According to Henry's law which states that the solubility of a gas in liquid is directly proportional to the pressure of the gas above the solution.

    Sg1 / P1 = Sg2 / P2,

    where Sg is the gas solubility, P is the gas pressure.

    Sg1 = 0.22

    P1 = 20kPA

    P2 = 115kPA

    Sg2 = ?

    Sg2 = Sg1 P2 / P1

    Sg2 = 0.22 * 115*10^3 / 20*10^3

    Sg2 = 25.3*10^3 / 20*10^3

    Sg2 = 1.265g/L

    the solubility of the gas in water at the new pressure is 1.265g/L
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased to 115 kPa? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers