What is the mass of aluminum that absorbed 952 J of energy and changed its temperature by

37.0 °C. (Specific Heat of aluminum is 0.900 J/g*°C)

28.59g

Explanation:

The following data were obtained from the question:

Heat Absorbed (Q) = 952 J

Change in temperature (ΔT) = 37°C.

Specific Heat capacity (C) = 0.9J/g°C

Mass (M) = ... ?

The mass of aluminium involved can be obtained as follow:

Q = MCΔT

952 = M x 0.9 x 37

Divide both side by 0.9 x 37

M = 952 / 0.9 x 37

M = 28.59g.

Therefore, the mass of aluminium is 28.59g

Mass = 28.59g

Explanation:

Q = 952J

Change in temperature = 37.0°C

Specific heat capacity = 0.90J/g°C

Mass = ?

Heat Energy (Q) = mc∇T

Q = heat energy

M = mass of substance

C = specific heat capacity of substance

∇T = change in temperature of substance

Q = mc∇T

952 = m * 0.90 * 37

952 = 33.3m

Solve for m

M = 952 / 33.3

M = 28.59g

The mass of aluminium required to use a heat energy of 952J is 28.59g