What is an important step to determine the number of grams of SO3 that can be produced by reacting 6 moles of SO2 with oxygen in the synthesis reaction below. 2 SO2 (g) + O2 (g) - >2 SO3 (g)

480.40 g.

Explanation:

According to the balanced equation:

2 SO₂ (g) + O₂ (g) → 2 SO₃ (g),

it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.

We can get the no. of moles of SO₃ produced:

∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.

∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.

Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:

mass = no. of moles x molar mass of SO₃ = (6.0 moles) (80.066 g/mol) = 480.396 g ≅ 480.40 g.