For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?

1019.27 g.

Explanation:

For the balanced reaction:

2Na + Cl₂ → 2NaCl,

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need →? mol of Cl₂.

∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na = (1 mol) (57.5 mol) / ((2 mol) = 28.75 mol.

∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂) (molar mass of Cl₂) = (28.75 mol) (35.453 g/mol) = 1019.27 g.