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9 January, 22:46

The decomposition of potassium chlorate yields oxygen gas. If the yield is 895%, how many grams of KClO3 are needed to produce 10.0 L of O2?

2KClO3 (s) - - > 2KCl (s) + 3 O2 (g)

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  1. 10 January, 02:40
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    The answer is either 38 g or 40. g KCLO3. If it 95% instead of 895%.
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