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6 November, 00:11

Calculate the molarity of the following solution: 2.30 moles of sodium chloride in 0.452 liters of solution.

A. 1.04 M

B. 5.01 M

C. 0.197M

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  1. 6 November, 01:30
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    B = 5.01M

    Explanation:

    n = 2.3mol, V = 0.452L, C=?

    Applying n = CV

    2.3 = C * 0.452

    C = 5.08M
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