F the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize?

Assuming the other part of the question is;

A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. (Assume KNO3 has a solubility of 14 g solute / 100 g water)

Answer;

26 g

Solution;

-X g of KNO3 / 130 g water = 14 g of KNO3 / 100 g water

X = 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water).

if you have 44.3g of KNO3 in 130 g of water at 0 degrees celsius and only 18.2 can dissolve then

44.2g - 18.2g = 26 g left undisolved which gives you the amount that would crystallize